dynimcally allocated array 2

 #include <stdio.h>  
 #include <stdlib.h>  
   
 void main()  
 {  
    double *ary;   //will be your dynamic 1d array  
    int num;       //your array element  
   
    //input your number of array element  
    printf("num: ");  
    scanf("%d", &num);  
   
    //syntax: number of block address times byte needed (sizeof) for double variable  
    ary = malloc(num * sizeof(double));     
   
    //fill the array (can be changed to any number) and display them  
    for(int i=0; i<num; i++)  
    {  
       ary[i] = i * i * 2.8;  
       printf("%.2f\n", ary[i]);  
    }  
   
    //must free the memory allocation to not make memory leak  
    if(ary) free(ary);  
 }  
   

dynamically allocated 2d array using an array of pointers

 #include <stdio.h>   
 #include <stdlib.h>   
     
  void main()   
  {   
    int row = 5, col = 3;   
    int i, j;   
    double *ar[row]; //will be your 2d array   
   
    for(i=0; i<row; i++)  //make it into 2d array
         ar[i] = malloc(sizeof(int)*col);  //get the column number of array
   
    for(i=0; i<row; i++)  
    {  
         for(j=0; j<col; j++)  
         {  
              ar[i][j] = (i + j) * 1.0;  //filling the array element
         }  
    }  
     
    for(i=0; i<row; i++)  
    {  
         for(j=0; j<col; j++)  
         {  
          printf("[%d][%d]=%.2f ", i, j, ar[i][j]);   //print the array after filling it
         }  
         printf("\n");  
    }  
   
    //must free the memorry allocation after using it  
    for(i=0; i<row; i++)  
         free(ar[i]);      
  } 

result:

[0][0]=0.00 [0][1]=1.00 [0][2]=2.00
[1][0]=1.00 [1][1]=2.00 [1][2]=3.00
[2][0]=2.00 [2][1]=3.00 [2][2]=4.00
[3][0]=3.00 [3][1]=4.00 [3][2]=5.00
[4][0]=4.00 [4][1]=5.00 [4][2]=6.00

dynamically allocated array

 #include <stdio.h>  
 #include <stdlib.h>  
   
 void main()  
 {  
     double *ar; //will be your array  
     double elem[] = {0.1, 0.2 ,0.3 ,0.4 ,0.5};   
     int num = 5, i;  
   
     printf("array number: %d\n", num);  
     for(i=0; i<num; i++)  
         printf("[%d]:%.2f\n", i, elem[i]);  
   
     printf("lets double it and put in your new array using malloc\n");  
     printf("--\n");  
   
     ar = malloc(sizeof(double)*num); //allocate the memory for your array  
   
     for(i=0; i<num; i++){  
       *(ar+i) = elem[i] * 2;  
     }  
   
     for(i=0; i<num; i++)   
         printf("array[%d]=%.2f\n", i, ar[i]);  
   
 free(ar); //must free the memorry allocation after using it  
 } 

result：

-------------- 

 array number: 5
[0]:0.10
[1]:0.20
[2]:0.30
[3]:0.40
[4]:0.50
lets double it and put in your new array using malloc
--
array[0]=0.20
array[1]=0.40
array[2]=0.60
array[3]=0.80
array[4]=1.00